Saturday, 8 August 2015

Bank Jobs Qualify in RRB CWE 3


Post Date
Last Date
Bank Name
Post Name
No. Post
Bank Website
07/08/2015
21/08/2015
Jharkhand Gramin Bank
Officer Scale I, II, Office Assistant
42
06/08/2015
20/08/2015
Sarva U.P. Gramin Bank
Officer Scale I, II, III, Office Assistant
275
31/07/2015
13/08/2015
Aryapuram Co-Operative Urban Bank Ltd.
Officer, Clerk
20
30/07/2015
13/08/2015
Madhyanchal Gramin Bank
Office Assistant
207
30/07/2015
13/08/2015
Paschim Banga Gramin Bank
Officer Scale I, II, III, Office Assistant
103
28/07/2015
12/08/2015
Uttarakhand Gramin Bank
Officer Scale II & III
43

Thursday, 6 August 2015

Syllabus of IBPS CWE 5 online examination


Online test questions except the English Language Test will be available in English and Hindi.
I] Preliminary Examination:
Sr. No.
Test Name
No. of Questions
Maximum Marks
Duration (Time)
1
English Language
30
30
1 Hour (Composite time of 60 Minutes)
2
Numerical Ability
35
35
3
Reasoning Ability
35
35
Total
100
100

II] Main Examination:
Sr. No.
Test Name
No. of Questions
Maximum Marks
Duration (Time)
1
Reasoning
40
40
2 Hour (Composite time of 120 Minutes)
2
English Language
40
40
3
Quantitative Aptitude
40
40
4
General Awareness(Related to Banking Industry)
40
40
5
Computer Knowledge
40
40
Total
200
200

Tuesday, 4 August 2015

Bank clerks exam in 2015

Apply Online for Clerks CWE V in 2015: ibps.in has released notification to conduct online examination for Clerks CWE V examination. Any graduate candidate can apply online from 11-08-2015 on ibps.in site. Candidates have to fulfill the criteria of Age Limit and Education Qualification.

Age limit: 20 years minimum age limit and 28 years is maximum age limit as on 01-08-2015, Age relaxation is applicable 5 years for SC/ ST, 3 years for OBC, 10 years for PWD & Others as per rules.

Educational Qualification: Candidate should possess Degree (Graduation) in any discipline from a recognized University by the Government of India.

Application Fee:Rs.100/- for SC/ ST/ PWD category candidates and Rs. 600/- for all others. Payment mode is online only through payment gateway on or before 01-09-2015.

How to Apply: Eligible candidates may apply online through IBPS’s website www.ibps.in from 11-08-2015 to 01-09-2015. After submission of online application form, candidates have to take print out of it for future purpose. System generated printout of the online application form, original and self attested photocopies of all relevant documents must be produced at the time of interview.

Very Important Dates candidates have to remember:
Starting Date to Apply Online and to Payment of Fee                      :11-08-2015
Last Date to Apply Online & Payment of Fee                                   :01-09-2015
Download of Call Letter for Pre-Examination Training                   :03-11-2015to17-11-2015
Download of Call letter for Online Preliminary Examination          : 18-11-2015 onwards
Online Examination-Preliminary                           :05-12-2015, 06-12-2015,12-12-2015, 13-12-2015
Declaration of Result of Preliminary Examination                           : December 2015
Download of Call letter for Online Main Examination                    : December 2015
Date of Online Main Examination                                                     :02-01-2016&03-01-2016
Declaration of Result of Main Examination                                     : January 2016

Sunday, 2 February 2014

Solved examples on Time and Distance

You have to understand some basic concepts before we start to solve problems on Time and Distance.
*Speed Definition: The time covered per unit time is called as speed.

Basic formula: Speed = (Distance/Time)
Manipulation of formula:     Time = (Distance/Speed)
                                                  Distance = (Speed * Time)
*Unit Conversion: If you want to convert speed from KMPH (Kilometres Per Hour) into m/s (metres per second) follow some  basic tricks.

1KMPH = (1*1000)/(60*60) metres/seconds
                =(1000/3600) m/s
                =10/36  m/s       
                =5/18 m/s
so  1 KMPH is 5/18 m/s.


Problem I] if you wants to convert speed from KMPH to m/s, multiply that number with (5/18)
i.e. 54 KMPH speed can be converted into m/s as (54)*(5/18)
                                                                                =3*5    (as 18 cancel 54)
                                                                                =15 m/s
Problem II] if you want to convert speed from m/s to KMPH, multiply that number with (18/5)
i.e. 25 m/s speed can be converted into KMPH as 25*(18/5)
                                                                                =5*18    (as 5 cancel 25)
                                                                                =90KMPH
*Average Speed = (Total distance traveled/ Total time taken)
Consider a bus traveling from A to B of distance d with the constant speed p and same bus travel back from B to A of same distance d with different constant speed q.

As per the speed formula Time = (Distance/Speed)
So        Total time taken = (Time while going)+(Time while coming back)
                                                  =(d/p)+(d/q)  
                                                =d{(p+q)/(pq)}

            Total distance traveled:(d+d)=2d
            By the formula
Average Speed = (Total distance traveled/ Total timer taken)
Average Speed = (2d/d{(p+q)/(pq)})
Average Speed = 2pq/(p+q)

*If a bus covers part of there journey at a constant speed p and remaining part of journey at a different constant speed q, and the distance traveled of the two part is in the ratio as m:n, then the Average Speed for entire journey is given as below
Average Speed = {(m+n)*(pq)}/(mq+np)

Previously asked in Bank Examinations, most important and Solved questions on Time and Distance

 1] Express 72 KMPH in metres/second?
Sol:         72 KMPH
                = 72*(5/18)
                = 4*5 m/s
                =20 m/s

2] Express 35 m/s in KMPH?
Sol:          35 m/s
                =35*(18/5)
                =7*18
                =126 KMPH

3] A car can travel 350KM in 4 hours. If its speed is decreased by 12.5 KMPH, How much time does the can takes to caver a distance of 450KM?
Sol: Speed  of the car
    Speed = (Distance/Time)
                Speed =(350/4)
                Speed =87.5 KMPH
Now speed of the  is reduced by 12.5
So new speed of the becomes (87.5-12.5) = 75 KMPH
If car travels with new speed of 75 KMPH, the time taken to cover distance of 450 is given by
Time = (Distance/ Speed)
Time = (450/75)
Time = 6 Hours
So if car travels with speed 75 KMPH, 6 hours will be required to cover 450 KM of distance.  

4] A bus can travel a certain distance travelling at a speed 60 KMPH and return with the speed 40 KMPH to the starting point. Find the average speed for entire journey?
Sol:      Average Speed = (Total distance traveled/ Total timer taken)
Average Speed = 2pq/(p+q)
Here no distance is mentioned, so do not about distance, only place the values of p and q
Where p is speed while going
And q is speed while coming back to the original point.
So,
Average Speed = (2*60*40)/(60+40)
                                =(4800)/100
                                =48 KMPH
Average Speed of the bus is 48 KMPH

5] A boy wins 200m race in 24 seconds, then his speed is?
Sol:          Speed = (Distance/Time)
                Speed = (200/24)
                Speed = 30 m/s
    Speed of the is 30 metres per second. 

6] If a train cover distance of 350km in one hour, What is the speed of the train in m/s?

Sol:          Speed = (Distance/Time)
                Speed  = (350km/1hr)
                Speed = 350 KMPH
To convert this speed from KMPH to m/s multiply it with 5/18
                Speed in m/s = 350*(5/18)
                                     = 97.22 m/s


7] A bus can travel a certain distance travelling at average speed 48 KMPH and it takes 3 hour to come back at starting point. Find the distance  covered by bus in one side?

Sol:        Let total distance covered by bus be x;
             one side distance covered by  bus = x/2;

Average Speed = (Total distance traveled/ Total timer taken)

48 = x/3;
X=144

Here, total distance covered by bus is 144 KM;
so,
one side distance covered by  bus = x/2;
                                                                =144/2
               
           one side distance covered by bus is 72 KM.

Thursday, 30 January 2014

computer storage devices and memory units

Area where we store Data or Information is called as computer data storage, in other way we can call it as storage or memory, this is a main functionality of computer. All type of manipulations and computations performed in the central processing unit (CPU) of a computer. As per the Von Neumann architecture, the CPU is made up of two main parts: control unit(CU) and arithmetic logic unit (ALU). The control unit controls the flow of data between the CPU and memory, while ALU performing any arithmetic or logical operations on data. The most common unit of storage is the byte, and 1 byte is equal to 8 bits. 1 bit is nothing but alphabet, numbers, pictures pixel, audio, video, or any other form of data or information can be converted into a string of bit, or binary number form, which is a value of 1 or 0. Below table will specify the units of memory storage.
Sr. No.
Unit
Description
1
1 Bit
A binary digits as 0 & 1
2
1 Nibble
A group of 4 bits
3
1 Byte
A group of 8 bits, and 2 nibbles
4
1 Word
It is group of byte, which varies from computer to computer, but is fixed for each computer
5
1 Kilobyte (KB)
1024 bytes
6
1 Megabyte (MB)
1024 KB
7
1 Gigabyte (GB)
1024 MB
8
1 Terabyte (TB)
1024 GB
9
1 Petabyte (PB)
1024 TB

Memory storage types:
Memory storage is again divided in three sections, which are primary storage, secondary storage and Tertiary storage.
I]Primary storage: CPU has direct access to Primary storage or it is referred simply as main memory or internal memory. As CPU is directly connected with main memory by memory bus so CPU continuously read the instruction from the memory and stored data to the main memory. This is volatile storage means it lose the data when there is power supply interrupt at any time. i.e. RAM(Random Access Memory)    
II]Secondary storage: Secondary storage is known as external memory or auxiliary storage, which is differs in functionality from primary storage as it is not directly accessible by the CPU. There is not direct connection from CPU. The computer usually uses its input/output channels to access secondary storage. Secondary storage does not lose the data when there is power supply interrupt at any time, so it is known as non-volatile storage. i.e. ROM(Read Only Memory), CD or DVD